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Two forces FA and FB are applied to an object? - Misunderstoodveil365 - 04-28-2014 07:05 PM
Two forces FA and FB are applied to an object whose mass is 13.0 kg. The larger force is FA. When both forces point due east, the object's acceleration has a magnitude of 1.00 m/s2. However, when FA points due east and FB points due west, the acceleration is 0.500 m/s2, due east. Find the magnitude of FA and the magnitude of FB.
- Mohammed - 04-28-2014 07:10 PM
F = m*a
1) Fa + Fb = 13 Kg * 1.00 m/s2 = 13
2) Fa - Fb = 13 Kg * 0.500 m/s2 = 6.5
solving these two equations yields :
Fa = 9.75 N
Fb = 3.25 N
- Steve4Physics - 04-28-2014 07:10 PM
F=ma
(FA+FB) = 13.0x 1.00 = 13.00
(FA-FB) = 13.0x 0.500 = 6.50
2FA = 13+6.50 = 19.50
FA = 9.75N
FB = 13.00 - 9.75
= 3.25N
- Oca - 04-28-2014 07:11 PM
FA > FB, m = 13 kg
1) FA + FB = ma > FA + FB = (13 kg)(1 m/s2) = 13 N > FA = 13 N - FB
2) FA - FB = (13kg)(0.5 m/s2) > FA = FB + 6.5 N
in 1) & 2) FA = 13N - FB = FB + 6.5 N > FB = 6.5N/2 = 3.25 N
FA = 9.75N and FB = 3.25N <<<< ANSWER
- Pegah Taheri - 04-28-2014 07:14 PM
the same as the upper answers
FA= 9.75
FB=3.25
- Johny - 04-28-2014 07:18 PM
apples