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+--- Thread: The car shown in the Figure below is pulled by the force FA and FB. Force FA has a magnitude of 50kN.? (/thread-164815.html)
The car shown in the Figure below is pulled by the force FA and FB. Force FA has a magnitude of 50kN.? - HSB - 06-17-2014 08:03 PM
a) Find the magnitude and direction FB, if the resultant for FR is directed along the x-axis and θ = 45°.
b) Find the value of θ for which FB is minimum if the resultant for FR is 80kN
http://imageshack.us/photo/my-images/9/screenshot20110923at800.png
- billrussell42 - 06-17-2014 08:14 PM
So the vector sum of Fa and Fb has to lie in the x axis, which means the y components have to add up to zero. or, the y components have to be equal.
Fay = 50k sin 20 = 17.1k
Fby = Fb sin 45 = 17.1
Fb = 17.1 / sin 45 = 24.2 kN. Direction is –45º as is stated
b) Fa = 50k, Fr = 80k
not enough info to solve.