Analytical chemistry question?

[Mighty man]

The answer is 2285.6 ppm .... how to get that answer I'm not sure ... but let me know if you find out how to find that answer @MannyRutinel on twitter

Nevermind I found out how to do it:
From the total mass of sample (n is #mol)

38.8626 = (n(FeCl3) x 162.2) + (n(KCL) x 74.5513)

from the titration # mol AgNO3 used gives us the total # mol Cl- = 5.6878 x 0.12622 = 0.717914 mol Cl-

so

0.717914 = 3n(FeCl3) + n(KCl)

use both equations to find n of each constituent. From n(KCL) calculate mass K then ppm is calculated like a mass percentage

ppm K = (mass K/38.8626g) x 10^6 ppm