If Fa=4N,W .Fnet=6N,W and has a mass of 3kg. What will be the Fb and Acceleration?
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04-28-2014, 10:49 AM
Post: #1
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If Fa=4N,W .Fnet=6N,W and has a mass of 3kg. What will be the Fb and Acceleration?
If Fa is 5000N,E
Fnet is 3000N,E Acceleration is 2m/s^,E What is the Fb and it's mass? Ads |
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04-28-2014, 10:51 AM
Post: #2
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1) Fa = 4 N, W.
Fnet = 6 N, W Acceleration = a Mass = M = 3 kg Fnet = Ma => 6 N, W = (3 kg)a => a = (6 N, W)/(3 kg) = (6/2) m/s², W Fa + Fb = Fnet => Fb = Fnet - Fa = 6 N, W - 4 N, W = (6 - 4) N, W = 2 N, W 2) Fa = 5000 N, E Fnet = 3000 N, E Fa + Fb = Fnet => Fb = Fnet - Fa Acceleration = a = 2 m/s², E => Fb = 3000 N, E - 5000 N, E = - 2000 N, E = 2000 N, W Mass = M Fnet = Ma => M = Fnet / a => M = (3000 N), E / (2 m/s²) E M = *(3000 / 2) kg = 1500 kg Ads |
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