um my math teacher couldn't figure out how to solve this surface area problem? 9th grade geometry.?

[TRish]

https://twitter.com/PashaEquestrian/stat...40/photo/1

please help!

[RickB]

It's not a surface area problem. It asks you to find the perimeter of a track. Tell your "teacher" to add the lengths of the two straight sides to the circumference of the half-circle sides.

[Aman]

answer is 254yards. just add the circumference of the semicircles and the straight sides

[?]

First, it asks for the perimeter not the surface area.
Second you must find the measurement of the arc. It gives you the diameter of the semi circle : 14
Since the formula to find the circumference of the arc in a semicircle is C=pi*r
When you substitute you get C= 3.14 * 7
C= 21.99 or ~22
once you add all the sides/arcs measurements together 22+22+105+105=254
so the perimeter of the track is 254 yards.

[TweetyQT]

well, first you would find the circumference of the half circles. To find that, you must do the diameter (14) times pi divided by 2. (because it is a half circle and therefor has half the perimeter.) You should come out with 21.98. THen, do the same to the other side. When you add the perimeters of both the half circles, you should get 43.96. then, you need to add the y lengths (105+105). Then add in the perimeters of the half circles. (210+43.96) (Dont forget to round!). if you did it correctly, your answer should be A.

Heres it in "math form"

3.14*14= 43.96
43.96/2=21.98
21.98+21.98= 43.96
105+105=210
210+43.96= 253.96
Rounded, your answer is 254 or A.

[Paige]

What geometry teacher wouldn't be able to figure out this easy geometry problem?
...epic fail at lying

nice try though