I have a question about stats...?

[hillbilly2837]

A random sample of 27 university students is selected and the time spent studying on a typical day, as well as the time spent using social media (Facebook, texting, Twitter, etc.) are recorded (both in minutes). The data are summarized in the table below:



Social Media.....Study Time.......Difference (Media - Study)
mean = 73 ........mean = 61 ..........mean = 12
std. dev. = 35....std. dev. = 39.......std. dev. = 20

Assume that all of the appropriate normality assumptions are satisfied.

(a) We would like to conduct a hypothesis test of H0: vs. Ha: at the 1% level of significance to determine whether there is evidence that the true mean time spent per day on social media for all university students differs from one hour. The decision rule for the appropriate test of significance is to reject H0 if the P-value is:

greater than 0.02.

greater than 0.005.

greater than 0.01.

less than or equal to 0.02.

less than or equal to 0.01.

less than or equal to 0.005.

(b) The value of the test statistic for the appropriate test of significance (rounded to two decimal places) is_____ .


© The P-value for the appropriate test of significance is between____ and _____ .


(d) What is the correct conclusion for the appropriate test of significance?

Fail to reject H0.

Reject H0.

(e) We would like to conduct a hypothesis test of at the 1% level of significance to determine whether there is evidence that university students spend more time on social media on an average day than they do studying. The hypotheses for the appropriate test of significance is____?

(f) The value of the test statistic for the appropriate test of significance (rounded to two decimal places) is _____ .


(g) The P-value for the appropriate test of significance is between____ and _____ .


(h) What is the correct conclusion for the appropriate test of significance?

Reject H0.

Fail to reject H0.

[Dhari]

Ixl.com try this

[Bail Out]

a. less than or equal to 0.01.
b. (73-60)/(35/sqrt27) = 1.93
c. 0.0536
d. Fail to reject