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How to do this log question?
08-16-2013, 06:50 PM
Post: #1
How to do this log question?
I'm raking my brains over this
solve :
ln(1+2x) - lnx^2 = 1

Thank you! 10 points to answer I find most helpful

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08-16-2013, 06:55 PM
Post: #2
 
"ln(2x+1) = ln x + 2

ln(2x + 1) - ln (x) = 2

ln [(2x+1) / x ] = 2

(2x + 1) / x = e^2

(2x+1) / x = 7.389

2x + 1 = 7.389x

5.389x = 1

x = 1 / 5.389

= 0.1856"

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