How to do this log question?
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08-16-2013, 06:50 PM
Post: #1
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How to do this log question?
I'm raking my brains over this
solve : ln(1+2x) - lnx^2 = 1 Thank you! 10 points to answer I find most helpful Ads |
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08-16-2013, 06:55 PM
Post: #2
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"ln(2x+1) = ln x + 2
ln(2x + 1) - ln (x) = 2 ln [(2x+1) / x ] = 2 (2x + 1) / x = e^2 (2x+1) / x = 7.389 2x + 1 = 7.389x 5.389x = 1 x = 1 / 5.389 = 0.1856" Ads |
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