Twitist Forums
OK, who is correct here? - Printable Version

+- Twitist Forums (http://twitist.com)
+-- Forum: Facebook forums (/forum-14.html)
+--- Forum: General facebook and life forums (/forum-25.html)
+--- Thread: OK, who is correct here? (/thread-123258.html)



OK, who is correct here? - FUNdie - 03-30-2014 11:35 AM

Take a look at this post and read the comments. Thanks!

https://www.facebook.com/photo.php?fbid=10201352634365866&set=a.1513079194959.2065469.1473806595&type=1&theater¬if_t=photo_reply


- Michael - 03-30-2014 11:46 AM

Well,

i'm afraid this is out of propos in this forum...

michael


- Gabor - 03-30-2014 11:48 AM

16 + 9 + 4 + 1 = 30

The basis must be a square otherwise the whole thing would fall down, not to mention the first wouldn't be supported properly based on the arrangement of the 3 visible ones.


- D.W. - 03-30-2014 11:55 AM

You can only see 16 balls, but assuming a symmetrical, three-dimensional structure, there are 30 balls.


- Polyhymnio - 03-30-2014 11:56 AM

It appears to be a three sided pyramid. If so, there are 20 balls.


- Paul - 03-30-2014 11:59 AM

You can see 16 balls in the picture.

Counting the balls that should be present if this picture was a physical pyramid there would be 4^2 + 3^2 + 2^2 + 1 = 30.