OK, who is correct here? - Printable Version +- Twitist Forums (http://twitist.com) +-- Forum: Facebook forums (/forum-14.html) +--- Forum: General facebook and life forums (/forum-25.html) +--- Thread: OK, who is correct here? (/thread-123258.html) |
OK, who is correct here? - FUNdie - 03-30-2014 11:35 AM Take a look at this post and read the comments. Thanks! https://www.facebook.com/photo.php?fbid=10201352634365866&set=a.1513079194959.2065469.1473806595&type=1&theater¬if_t=photo_reply - Michael - 03-30-2014 11:46 AM Well, i'm afraid this is out of propos in this forum... michael - Gabor - 03-30-2014 11:48 AM 16 + 9 + 4 + 1 = 30 The basis must be a square otherwise the whole thing would fall down, not to mention the first wouldn't be supported properly based on the arrangement of the 3 visible ones. - D.W. - 03-30-2014 11:55 AM You can only see 16 balls, but assuming a symmetrical, three-dimensional structure, there are 30 balls. - Polyhymnio - 03-30-2014 11:56 AM It appears to be a three sided pyramid. If so, there are 20 balls. - Paul - 03-30-2014 11:59 AM You can see 16 balls in the picture. Counting the balls that should be present if this picture was a physical pyramid there would be 4^2 + 3^2 + 2^2 + 1 = 30. |