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The car shown in the Figure below is pulled by the force FA and FB. Force FA has a magnitude of 50kN.?
06-17-2014, 08:14 PM
Post: #2
billrussell42 Offline
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So the vector sum of Fa and Fb has to lie in the x axis, which means the y components have to add up to zero. or, the y components have to be equal.

Fay = 50k sin 20 = 17.1k
Fby = Fb sin 45 = 17.1
Fb = 17.1 / sin 45 = 24.2 kN. Direction is –45º as is stated

b) Fa = 50k, Fr = 80k
not enough info to solve.
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[] - billrussell42 - 06-17-2014 08:14 PM

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